2.4.1 The Euclidean Algorithm (a≤b<0)


Lemma (will be proved)
a=qb+r⇒gcd(a,b)=gcd(b,r)
Proof of gcd(a,b)=rn

pf

example
숫자가 클수록 모든 positive divisor을 구하기는 어렵다

정리
- prove the Euclidean Algorithm
- We can compute the gcd(a,b) using Euclidean Algorithm (even for large a and b)
2.4.2 Find x,y∈Z with ax+by=gcd(a,b)
유클리드 호제법의 응용


답중의 하나를 위의 방법으로 구할 수 있다.
Theorem 2.7

Euclidean Algorithm 이용해서 증명함
정리
- We can find x,y∈Z s.t. ax+by=gcd(a,b) using the Euclidean Algorithm
2.4.3 The Least Common Multiple
Definition 2.4
Given a,b∈Z(a=0 or b=0), the least common multiple of a and b is the positive integer m satisfying
(a) a∣m and b∣m (common multiple)
(b) a∣c and b∣c⇒m≤c (least)
In this case, we write m=lcm(a,b)
Theorem 2.8
gcd(a,b)lcm(a,b)=ab
Corollary 2.8
For any a,b∈N,lcm(a,b)=ab⟺gcd(a,b)=1
Proof of Theorem 2.8
정리
- We can write the definition of lcm(a,b)
- We can prove the relation between gcd(a,b) and lcm(a,b)
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